Question on Diode and Resistor in Series
페이지 정보
작성자 김준하 댓글 1건 조회 736회 작성일 20-04-08 00:07본문
Hello, I have a question about the following image from the textbook on page 91.
Since there is a voltage drop due to the resistor, shouldn't the diode (D1) turn on when V_in exceeds V_R + V_B1 + V_D,on ?
It seems like all of the other questions/examples from the textbook ignore the voltage drop due to the resistor, and I don't quite understand the reason for it.
Thank you.
(I have attached the example figure below).
Since there is a voltage drop due to the resistor, shouldn't the diode (D1) turn on when V_in exceeds V_R + V_B1 + V_D,on ?
It seems like all of the other questions/examples from the textbook ignore the voltage drop due to the resistor, and I don't quite understand the reason for it.
Thank you.
(I have attached the example figure below).
댓글목록
TA님의 댓글
TA 작성일
It seems that the question assumes an ideal diode.
When the Vin is within [-Vdon - Vb2, Vdon + Vb1],
both diodes D1 and D2 are off so the current is 0.
When the Vin is Vdon + Vb1, diode D1 is almost on and the current is almost zero.
Therefore, you can ignore the voltage drop in this case so the Vout is same as Vin.